Bar Weight
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| Golf Advice |
Determine the weight of the bar and the position of the center of gravity.?
A non-uniform bar rests across two supports that are 20 ft apart. When loads of 200 lbs., 4 ft from end A and 150 lbs, 6 ft from end B are on the bar, end A supports 233 lbs and B supports 197 lbs. Determine the weight of the bar and the position of the center of gravity.
Down ward forces = [200 + 150 + W] .lb f.
W is the weight of the bar.
Upward force = 233 + 197.
For equilibrium
[200 + 150 + W] = 233 + 197.
W = 80 lb f.
================================
Taking moment about A, and taking that A is at left side.
Upward forces produce anti clockwise moments and down ward forces produce clockwise moments
.
The moment of 200 lb f about A is zero.
150*its distance from A = 200* 4 + 80* its distance from A.
150 *14 = 800 + 80 d.
d = 16.25 ft.


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